A water tank has steps inside it. A monkey is sitting on the topmost step (i.e., the first step). The water level is at the ninth step.(i) He jumps 3 steps down and then jumps back 2 steps up. In how many jumps will he reach the water level?
Given: A water tank has steps inside it. A monkey is sitting on the topmost step $(i.e.,\ the\ first\ step)$. The water level is at the ninth step. He jumps $3$ steps down and then jumps back $2$ steps up.
To do: To find the number of jumps, the monkey will take to reach the water level.
Solution:
$1st\ jump\ 1+3=4th\ step\ 1+3=4th\ step$
$2nd\ jump\ 4-2=\ 2nd\ step\ 4−2= 2nd\ step$
$3rd\ jump\ 2+3=5th\ step\ 2+3=5th\ step$
$4th\ jump\ 5-2=\ 3rd\ step\ 5−2= 3rd\ step$
$5th\ jump\ 3+3=6th\ step\ 3+3=6th\ step$
$6th\ jump\ 6-2=4th\ step\ 6−2=4th\ step$
$7th\ jump\ 4+3=7th\ step\ 4+3=7th\ step$
$8th\ jump\ 7-2\ =\ 5th\ step\ 7−2 = 5th\ step$
$9th\ jump\ 5+3=\ 8th\ step\ 5+3= 8th\ step$
$10th\ jump\ 8-2=\ 6th\ step\ 8−2= 6th\ step$
$11th\ jump\ 6+3=\ 9th\ step\ 6+3= 9th\ step$
Thus, the monkey will reach $9th$ step in $11th$ jumps.
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