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A tree of height 4.8 m is broken into three pieces in the ratio 3 : 4 : 5. Find the length of each piece.
Given:
Total height of the tree = 4.8 m and tree is broken into three pieces in the ratio 3 : 4 : 5.
To find:
We have to find the value of the Length of each piece.
Solution:
Let the common factor be = a
So,
1st piece = 3a
2nd piece = 4a
3rd piece = 5a
Therefore, according to the problem:
3a $+$ 4a $+$ 5a = 4.8 m
12a = 4.8 m
a = $\frac{4.8}{12}$ m
a = 0.4 m
Now,
1st piece = 3a = 3 $\times$ 0.4 = 1.2 m
2nd piece = 4a = 4 $\times$ 0.4 = 1.6 m
3rd piece = 5a = 5 $\times$ 0.4 = 2.0 m
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