A survey regarding the height (in cm) of 51 girls of class X of a school was conducted and the following data was obtained:
Height in cm | Number of Girls |
Less than 140
| 4 |
Less than 145
| 11 |
Less than 150
| 29 |
Less than 155
| 40 |
Less than 160
| 46 |
Less than 165
| 51 |
Find the median height.
Given:
A survey regarding the height (in cm) of 51 girls of class X of a school was conducted.
To do:
We have to find the median height.
Solution:
Arranging the data in class intervals, we get,
Here,
$N=51$
This implies,
$\frac{N}{2}=\frac{51}{2}=25.5$
The cumulative frequency just greater than 25.5 is 29 and the corresponding class is 145 – 150.
This implies, 145 – 150 is the median class.
Therefore,
$l = 145, f= 18, F =11$ and $h = 150-145=5$
Median $=l+(\frac{\frac{\mathrm{N}}{2}-\mathrm{F}}{f}) \times h$
Therefore,
Median $=145+\frac{25.5-11}{18}\times 5$
$=145+\frac{14.5}{18}\times 5$
$=145+\frac{72.5}{18}$
$=145+4.03$
$=149.03$
The median height is 149.03 cm.
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