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A sum of money doubles itself in 8 years. What is the rate of interest?
Given :
A sum of money doubles itself in 8 years.
To do :
We have to find the rate of interest.
Solution :
Let the Principal be $P$ and rate percent be $R$.
This implies,
Amount $A=2P$
We know that,
$Amount (A) = Principal (P) + Simple Interest (SI)$
$Simple Interest (SI) = Amount (A) - Principal (P)$
$SI=2P-P$
$SI=P$
$SI = \frac{PRT}{100}$
Therefore,
$P = \frac{(P \times R \times 8)}{100}$
$100 = R \times 8$
$R = \frac{100}{8}$
$R = 12.5$
The rate percent is 12.5%.
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