A submarine was floating at a depth of $ 640 \mathrm{~m} $ below the sea level. If it ascends 230 metres, what will be its new position? Express the position in terms of depth.

Given:

A submarine was floating at a depth of \( 640 \mathrm{~m} \) below the sea level.

It ascends 230 metres.

To do:

We have to find the new position.

Solution:

Let the sea level be $0$ and the depth below the sea level be negative.

This implies,

Initial position of the submarine $=-640\ m$

Final position of the submarine $=$ Initial position $+$ Height ascended

$=-640+230\ m$

$=-410\ m$ 

The final position of the submarine is $410\ m$ below the sea level.

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Updated on: 10-Oct-2022

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