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A square water tank has its side equal to $ 40 \mathrm{~m} $. There are four semi-circular grassy plots all round it. Find the cost of turfing the plot at $ ₹ 1.25 $ per square metre (Take $ \pi=3.14) $.
Given:
A calf is tied with a rope of length \( 6 \mathrm{~m} \) at the corner of a square grassy lawn of side \( 20 \mathrm{~m} \).
The length of the rope is increased by \( 5.5 \mathrm{~m} \).
To do:
We have to find the increase in area of the grassy lawn in which the calf can graze.
Solution:
Side of the square water tank $= 40\ m$
Radius of each semi-circular grassy plot $=\frac{40}{2}\ m=20\ m$
Rate of turfing the plot per $\mathrm{m}^{2}=Rs.\ 1.25$
Area of a semi-circular plot of radius $r$ is $\frac{1}{2} \pi r^{2}$.
Therefore,
Area of four semicircular plots around the square $=4 \times \frac{1}{2} \pi r^{2}$
$=2 \times 3.14 \times(20)^{2} \mathrm{~m}^{2}$
$=2 \times 3.14 \times 400 \mathrm{~m}^{2}$
$=800 \times 3.14 \mathrm{~m}^{2}$
$=2512 \mathrm{~m}^{2}$
Total cost of turfing $=Rs.\ 2512 \times 1.25$
$=Rs.\ 3140$
The cost of turfing the plot is Rs. 3140.