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# A six digit number, when divided by 7, gives a remainder of 2. Which of these can be added to the number so that the remainder becomes 0:

**Given:**A six-digit number, when divided by 7, gives a remainder of 2.

**To do:**Find which number can be added to the number so that the remainder becomes 0?

**Answer**

Let the six-digit number be = $x$

On dividing $x$ by $7$, there is a remainder of 2. Let 7 goes $y$ times in $x$

So $x = 7y + 2$

**If 5 is added to the number $x$, it becomes $7y + 2 + 5 = 7(y+1)$**

**So it becomes divisible by 7 leaving a remainder of 0.**

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