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A six digit number, when divided by 7, gives a remainder of 2. Which of these can be added to the number so that the remainder becomes 0:
Given:A six-digit number, when divided by 7, gives a remainder of 2.
To do: Find which number can be added to the number so that the remainder becomes 0?
Answer
Let the six-digit number be = $x$
On dividing $x$ by $7$, there is a remainder of 2. Let 7 goes $y$ times in $x$
So $x = 7y + 2$
If 5 is added to the number $x$, it becomes $7y + 2 + 5 = 7(y+1)$
So it becomes divisible by 7 leaving a remainder of 0.
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