A six digit number, when divided by 7, gives a remainder of 2. Which of these can be added to the number so that the remainder becomes 0:


Given:A six-digit number, when divided by 7, gives a remainder of 2.

To do:  Find which number can be added to the number so that the remainder becomes 0?

Answer
Let the six-digit number be = $x$

On dividing $x$ by $7$, there is a remainder of 2. Let 7 goes $y$ times in $x$

So $x = 7y + 2$

If 5 is added to the number $x$, it becomes $7y + 2 + 5 = 7(y+1)$

So it becomes divisible by 7 leaving a remainder of 0.

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Updated on: 10-Oct-2022

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