A shopkeeper sells a pen set at $30$ % profit to another shopkeeper who sells it at a loss of $30$ %. If price of pen set $â‚¹\ 150$ , what is net profit or loss on total transaction?

Academic Mathematics NCERT Class 8

Given: A shopkeeper sells a pen set at $30$ % profit to another shopkeeper who sells it at a loss of $30$ %. And the price of pen set $₹\ 150$.

To do: To find the net profit or loss on total transaction.

Solution:

As given, $1^{st}$ Shopkeeper sells a pen at $X=30$ % Profit to another $2^{nd}$ shopkeeper

$2^{nd}$ Shopkeeper sold it at $Y=30$ % Loss

On using formula of net profit or loss $=X+Y+( \frac{XY}{100})$

Therefore, net profit or loss $=X+Y+( \frac{XY}{100})$

$\Rightarrow 30+( -30)+ \frac{( 30)(-30)}{100}$

$\Rightarrow -9$ %

Therefore, total net loss is $9$ %

After $9$ % loss, the price of pen$=150-( \frac{150\times9}{100})$

$=150-13.5$

$=₹\ 136.5$

Thus, the net loss is $₹\ 107.52$.

Simply Easy Learning

Updated on: 10-Oct-2022

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