A shopkeeper had a coil of electric wire measuring $60\ m$ long. He sold $\frac{2}{5}$ of it to the first customer and $10$ whole $\frac{1}{2}$ to theSecond customer what length of electric wire is left with him.

Academic Mathematics NCERT Class 8

Given: A shopkeeper had a coil of electric wire measuring $60\ m$ long. He sold $\frac{2}{5}$ of it to the first customer and $10$ whole $\frac{1}{2}$ to the Second customer.

To do: to find the length of electric wire is left with him.

Solution:

Total length$=60\ m$

Wire sold to first costumer$=\frac{2}{5}$ of the wire$=\frac{2}{5}\times 60$

$=\frac{120}{5}$

$=24\ m$

Wire sold to second costumer$=10$ whole $\frac{1}{2}$ of the wire$=\frac{10\times2+1}{2}$

$=\frac{21}{2}$

$=10.5\ m$

Left length of the wire$=60-( 24+10.5)$

$=60-( 34.5)$

$=25.5\ m$

Thus $25.5\ m$ wire is left with him.

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Updated on: 10-Oct-2022

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