A sector of a circle of radius 4 cm contains an angle of $30^o$. Find the area of the sector.

Given:

Radius of the circle $=4\ cm$.

Angle subtended by the sector $=30^o$

To do:

We have to find the area of the sector.

Solution:

Area of the sector subtending $\theta$ at the centre $=\pi r^{2} \times \frac{\theta}{360^{\circ}}$

Therefore,

Area of the given sector $=\pi(4)^{2} \times \frac{30^{\circ}}{360^{\circ}} \mathrm{cm}^{2}$

$=16 \pi \times \frac{1}{12} \mathrm{~cm}^{2}$

$=\frac{4\pi}{3} \mathrm{cm}^{2}$

The area of the sector is $\frac{4\pi}{3} \mathrm{cm}^{2}$.

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

734 Views

Kickstart Your Career

Get certified by completing the course

Get Started