A road roller takes 750 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is $ 84 \mathrm{~cm} $ and length is $ 1 \mathrm{~m} $.

Given:

A road roller takes 750 complete revolutions to move once over to level a road.

The diameter of a road roller is \( 84 \mathrm{~cm} \) and length is \( 1 \mathrm{~m} \).

 To do:

We have to find the area of the road.

Solution:

Diameter of the road roller$=84\ cm$

Radius of the road roller$=\frac{84}{2}=42\ cm$

Area of the road $=$Number of revolutions $\times$ Area covered in 1 revolution

Area covered in 1 revolution $=$ Lateral surface area of the cylinder

$=2\pi rh$

$=2\times\frac{22}{7}\times\frac{42}{100}\times1$

$=\frac{44\times6}{100}\ m^2$

Area of the road $=750\times\frac{264}{100}\ m^2$

$=15\times132\ m^2$

$=1980\ m^2$

The area of the road is $1980\ m^2$.

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Updated on: 10-Oct-2022

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