A pond of depth $20cm$ is filled with water of refractive index $\frac{4}{3}$. Calculate the apparent depth of the pond when viewed normally.

$Refractive\ index=\frac{Real\ depth}{Apparent\ depth}\phantom{\rule{0ex}{0ex}}$

$n=\frac{x}{y}$

Substiuting the given values in the expression we get-

$\frac{4}{3}=\frac{20}{y}\phantom{\rule{0ex}{0ex}}$

$y=\frac{20\times 3}{4}\phantom{\rule{0ex}{0ex}}$

$y=15m\phantom{\rule{0ex}{0ex}}$

Hence, the apparent depth of the pond when viewed normally will be 15m.

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Updated on: 10-Oct-2022

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