A patient in a hospital is given soup daily in a cylindrical bowl of diameter $ 7 \mathrm{~cm} $. If the bowl is filled with soup to a height of $ 4 \mathrm{~cm} $, how much soup the hospital has to prepare daily to serve 250 patients?

 Given:

A patient in a hospital is given soup daily in a cylindrical bowl of diameter $7\ cm$.

The bowl is filled with soup to a height of $4\ cm$.

To do:

We have to find the volume of soup the hospital has to prepare daily to serve 250 patients.

Solution:

Diameter of the cylindrical bowl $= 7\ cm$

This implies,

Radius of the bowl $(r) =\frac{7}{2}\ cm$

Level of soup in the bowl $= 4\ cm$

Therefore,

The volume of soup in one bowl for one patient $=\pi r^{2} h$

$=\frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times 4$

$=154 \mathrm{~cm}^3$

Therefore,

Soup for 250 patients $=154 \times 250$

$=38500 \mathrm{~cm}^{3}$

$=\frac{38500}{1000}$ litres

$=38.5$ litres

Hence, the hospital has to prepare $38.5$ litres daily to serve 250 patients.