A particle experiences constant acceleration for $20\ seconds$ after starting from rest. If it travels a distance $D_1$ in the first $10\ seconds$ and distance $D_2$ in the next $10\ seconds$ then:a. $D_2=D_1$b. $D_2=2D_1$c. $D_2=3D_1$d. $D_2=4D_1$

For the first 10 seconds:

Here, initial velocity $u=0$

Time $t=10\ s$

Let $a$ be the constant acceleration.

On using the equation of motion $s=ut+\frac{1}{2}at^2$

$D_1=0+\frac{1}{2}a\times10^2$

Or $D_1=50a$   ....... $(i)$

For next 10 seconds:

velocity after 10 seconds $v=u+at=0+a\times10=10a$

Initial velocity $=10a$

Therefore, $D_2=10a\times10+\frac{1}{2}a\times10^2$

Or $D_2=100a+50a$

Or $D_2=150a$   ....... $(ii)$

On comparing, $(i)$ and $(ii)$

We have $D_2=3D_1$

Therefore, option c. is correct.

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

169 Views

Kickstart Your Career

Get certified by completing the course

Get Started