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A number is selected at random from the numbers 1 to 30. The probability that it is a prime number:
$( A) \ \frac{2}{3}$
$( B) \ \frac{1}{6}$
$( C) \ \frac{1}{3}$
$( D) \ \frac{11}{30}$
Given: A number is selected at random from the numbers 1 to 30.
To do: To find the probability that it is a prime number.
Solution: Total number of possible outcomes $=30$
Prime numbers between 1 to 30 are 2, 3, 5, 7, 11, 13, 17, 19, 23 and 29
Total number of favourable outcomes $=\ 10$
Probability of selecting a prime number from 1 to 30$=\frac{Total\ number\ of\ favourable\ outcomes}{Total\ number\ of\ outcomes}$
$=\frac{10}{30}$
$=\frac{1}{3}$
Hence, The correct option is $( C)$
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