A multistorey building has 25 floors above the ground level each of height 5m. It also has 3 floors in the basement each of height 5m. A lift in building moves at a rate of 1m/s. If a man starts from 50m above the ground, how long will it take him to reach at 2nd floor of basement?

Given: A multistorey building has 25 floors above the ground level each of height 5m.

It also has 3 floors in the basement each of height 5m.

A lift in building moves at a rate of 1m/s.

To do: Find how long will it take for a to reach a 2nd floor of the basement if he starts from 50m above?

Solution:

The depth of 2nd floor of basement = $ 2 \times 5 = 10m$

The height from ground level from which lift starts = $50$ m

Total distance traveled by the lift = $50 + 10 = 60$m

Speed of the lift = 1m/s

Time is taken by the lift to reach the second floor of the basement

= $\frac{Distance}{Speed} = 60 m/s

=1m/s = 60 seconds or 1 minute

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Updated on: 10-Oct-2022

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