A motorcycle moving with a speed of $5\ m/s$ is subjected to an acceleration of $0.2\ m/s^2$. Calculate the speed of the motorcycle after 10 seconds, and the distance travelled in this time.

Academic Physics NCERT Class 9

Initial velocity of the motorcycle $u=5\ m/s$

Acceleration $a=0.2\ m/s^2$

Time $t=10\ sec.$

Let $v$ be the final velocity of the motorcycle.

On using the equation of motion:$v=u+at$

Or $v=5+0.2\times10$

Or $v=5+2$

Or $v=7\ m/s$

Distance travelled $s=ut+\frac{1}{2}at^2$

Or $s=5\times10+\frac{1}{2}\times0.2\times10^2$

Or $s=50+10$

Or $s=60\ m$

Simply Easy Learning

Updated on: 10-Oct-2022

35 Views

Kickstart Your Career

Get certified by completing the course

Advertisements