A motor cycle moving with a speed of $5\ m/s$ is subjected to an acceleration of $0.2\ m/s^2$. Calculate the speed of the motor cycle after $10\ second$.

Here initial velocity $u=5\ m/s$

Acceleration $a=0.2\ m/s^2$

Time $t=10\ second$

Let $v$ be the final velocity. 

On using the first equation of the motion, $v=u+at$

$v=5+0.2\times10$

Or $v=7\ m/s$

Therefore, the speed of the motorcycle after $10\ second$ is $7\ m/s$

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Updated on: 10-Oct-2022

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