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A motor boat whose speed in still water is 9 km/hr in still water, goes 15 km downstream and comes back to the same spot, in a total time of 3 hours 45 minutes. Find the speed of the stream.
Given:
A motor boat whose speed in still water is 9 km/hr in still water, goes 15 km downstream and comes back to the same spot, in a total time of 3 hours 45 minutes.
To do:
We have to find the speed of the stream.
Solution:
Let the speed of the stream be $x$ km/hr.
This implies,
Speed of the boat downstream$=x+9$ km/hr
Speed of the boat upstream$=9-x$ km/hr
Time taken by the boat to go 15 km downstream$=\frac{15}{x+9}$ hours
Time taken by the boat to go 15 km upstream$=\frac{15}{9-x}$ hours
$45$ minutes in hours$=\frac{45}{60}=\frac{3}{4}$
$3$ hours $45$ minutes $=3+\frac{3}{4}=\frac{4\times3+3}{4}=\frac{15}{4}$ hours
Therefore,
$\frac{15}{x+9}+\frac{15}{9-x}=\frac{15}{4}$
$\frac{15(9-x)+15(x+9)}{(x+9)(9-x)}=\frac{15}{4}$
$\frac{135-15x+15x+135}{(9)^2-x^2}=\frac{15}{4}$
$\frac{270}{81-x^2}=\frac{15}{4}$
$4(270)=15(81-x^2)$ (On cross multiplication)
$4(18)=81-x^2$
$x^2+72-81=0$
$x^2-9=0$
$x^2=9$
$x=3$
The speed of the stream is $3$ km/hr.