A man sold a bicycle at 5% profit. If the cost had been 30% less and the selling price ₹63 less, he would have made a profit of 30%. What was the cost price of the bicycle ?
To do: Find C.P of bicycle.
Solution:
Let C.P. of the bicycle = Rs.$100$
In the 1st case :
When Profit = $5% $;
S.P. = Rs. $(100 + 5)$ = Rs. $105$
In the 2nd case:
C.P. = $100 – \frac{30}{100} \times 100$
= Rs. $100 – 30 = Rs. 70$
Profit = 30%
S.P. = $\frac{100 + Profit}{100} \times$ C.P.
= $\frac{100 + 30}{100 } \times. 70 = \frac{130}{100} \times 70$
= Rs. $\frac{130 \times 70}{100} = Rs. 91$
Difference of two selling prices = Rs. $105 -$ Rs. $91$ = Rs. $14$
If difference is Rs. $14$ then C.P. of the bicycle is Rs. $100$
“ Re.1 “ = Rs. $\frac{100}{14}$
Rs. 63 “ = Rs. $\frac{100}{14} \times 63$
= Rs. $\frac{100 \times 63}{14}$ = Rs. $50 \times 9$
= Rs. 450
Therefore, the cost price is Rs 450
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