A hollow garden roller, $63\ cm$ wide with a girth of $440\ cm$, is made of $4\ cm$ thick iron. Find the volume of the iron.

 Given:

A hollow garden roller, $63\ cm$ wide with a girth of $440\ cm$, is made of $4\ cm$ thick iron.

To do:

We have to find the volume of the iron.

Solution:

Width of hollow cylinder $(w) = 63\ cm$

Girth $= 440\ cm$

This implies,

Radius $r=\frac{\text { Perimeter }}{2 \pi}$

$=\frac{440 \times 7}{2 \times 22}$

$=70 \mathrm{~cm}$

Thickness of iron $=4 \mathrm{~cm}$

Therefore,

Inner radius $=70-4$

$=66 \mathrm{~cm}$

Volume of the iron $=\pi h (\mathrm{R}^{2}-r^{2})$

$=\frac{22}{7} \times 63 \times(70^{2}-66^{2})$

$=198(70+66)(70-66)$

$=198 \times 136 \times 4$

$=107712 \mathrm{~cm}^{3}$

The volume of the iron is $107712 \mathrm{~cm}^{3}$.

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Updated on: 10-Oct-2022

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