A girl is wearing a pair of flat shoes. She weighs $550\ N$. The area of contact of one shoe with the ground is $160\ cm^2$. What pressure will be exerted by the girl on the ground :
(a) if she stands on two feet ?
(b) if she stands on one foot ?


Given: Weight of the girl $W=550\ N$

Are of contact fo one shoe $A=160\ cm^2=160\times10^{-4}\ m^2$

(a). When the girl stands on two feet:

Area of the contact $=2\times160\times10^{-4}\ m^2$

$=320\times10^{-4}\ m^2$

Exerterd pressure $P=\frac{wieght(W)}{area(A)}$

$=\frac{550}{320\times10^{-4}}$

$=1.71\times10^4\ N/m^2$

Therefore, when the girl stands on two feet, the pressure exerted by the girl is $1.71\times10^4\ N/m^2$.

(b).  When the girl stands on one foot:


Exerted pressure by the girl $P=\frac{550\ N}{160\times10^{-4}\ m^2}$

$=3.43\times10^4\ N/m^2$

Therefore, when the girl stands on one foot, the pressure exerted by the girl is $3.43\times10^4\ N/m^2$.

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Updated on: 10-Oct-2022

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