A force of $10\ N$ displaces a body by a distance of $2\ m$ at an angle $60^{o}$ to its own direction. Find the amount of work done.

Academic Physics NCERT Class 9

Here given, Force Applied $F=10\ N$, Displacement $d=2\ m$, Angle $\theta=60^{\circ}$

Therefore, work done $W=Fd\cos\theta$

$=10\ N\times2\ m\times\cos60^{\circ}$

$=20\times\frac{1}{2}$

$=10\ Joule$.

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Updated on: 10-Oct-2022

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