A force of $10\ N$ acted upon a body and the body moves $10\ m$. Find the work done.

Academic Physics NCERT Class 9

Here given:

Force acted upon the body $F=10\ N$

Displacement $d=10\ m$

Therefore, Work done $W=F\times d$

$=10\ N\times 10\ m$

$=100\ Joule$

Thus, the work done is $100\ Joule$.

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

42 Views

Does work done depend upon the velocity of the body?
A force of $10\ N$ displaces a body by a distance of $2\ m$ at an angle $60^{o}$ to its own direction. Find the amount of work done.
How much work is done when a force of 1 N moves a body through a distance of 1 m in its direction?
How much work is done when a force of $1\ N$ moves a body through a distance of $1\ m$ in its own direction?
A body of mass $100\ kg$ is lifted up by $10\ m$. Find: (i) the amount of work done. (ii) potential energy of the body at that height $(value\ of\ g=10\ m/s^2)$.
A body acted upon by two forces of 200 N and 3 N,in the same direction. What is the resultant force acting on it?
(a) When do we say that work is done? Write the formula for the work done by a body in moving up against gravity. Give the meaning of each symbol which occurs in it. (b) How much work is done when a force of 2 N moves a body through a distance of 10 cm in the direction of force?
One-joule work is said to be done when (a) a force of 1 N displaces a body by 1 cm (b) a force of 1 N displaces a body by 1 m (c) a force of 1 dyne displaces a body by 1 m (d) a force of 1 dyne displaces a body by 1 cm
Write the formula for work done on a body when the body moves at an angle to the direction of force. Give the meaning of each symbol used.
Give one example each where:(a) a force moves a stationary body.(b) a force stops a moving body.(c) a force changes the speed of a moving body.(d) a force changes the direction of a moving body. (e) a force changes the shape (and size) of a body.
(a) What happens to the work done when the displacement of a body is at right angles to the direction of force acting on it? Explain your answer.(b) A force of $50\ N$ acts on a body and moves it a distance of $4\ m$ on a horizontal surface. Calculate the work done if the direction of force is at an angle of $60^{o}$ to the horizontal surface.
The initial velocity of a body becomes from $10\ m/s$ to $20\ m/s$ in $5\ seconds$. Find the acceleration of the body.
A body starts moving from rest and its velocity becomes $10\ m/s$ in $5\ seconds$. Find the acceleration of the body.
A body starts moving from rest and its velocity becomes $30\ m/s$ in $10\ seconds$. Find the acceleration of the body.
When is the work done by a force on a body: (a) positive, (b) negative, and (c) zero?

Kickstart Your Career

Get certified by completing the course

Get Started

Advertisements