A dealer sold 75 pencils everyday for 16 days and 90 pencils everyday for 14 days. He still has 2 dozen pencils left. How many pencils did he have to start with?
Given: A dealer sold 75 pencils everyday for 16 days and 90 pencils everyday for 14 days. He still has 2 dozen pencils left.
To find: Here we have to find the number of pencils dealer had at the start.
Solution:
A dealer sold 75 pencils everyday for 16 days:
Total number of pencils sold = 75 $\times$ 16
Total number of pencils sold = 1200
A dealer sold 90 pencils everyday for 14 days:
Total number of pencils sold = 90 $\times$ 14
Total number of pencils sold = 1260
Also,
Number of pencil left = 2 dozen
We know, 1 dozen = 12
Number of pencil left = 2 $\times$ 12
Number of pencil left = 24
Now,
Total pencils dealer had at the start = Total pencils sold $+$ Number of pencil left
Total pencils dealer had at the start = 1200 $+$ 1260 $+$ 24
Total pencils dealer had at the start = 2484
So, dealer had 2484 pencils at the start.
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