A dealer bought 100 articles for rupees 4000. 20 articles broke during transportation. At what rate must he sell the remaining articles to gain 10%?

Given :

A dealer bought 100 articles for rupees 4000.

20 articles broke during transportation.

To find :

We have to find the price he should sell the remaining articles to have a gain of 10%.

Solution :

Cost price of 100 articles $=Rs.\ 4000$

Total number of remaining articles $=100-20=80$

Gain$ \% =10 \%$ 

This implies,

SP $=$CP$+10 \%$ of CP

$=4000+\frac{10}{100}\times4000$

$=4000+400$

$=4400$

Selling price of 80 articles $=Rs.\ 4400$

Therefore,

Selling price of each article $=\frac{4400}{80}$

$=Rs.\ 55$

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Updated on: 10-Oct-2022

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