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A cylinder, whose height is $3\ m$, is open from top. The circumference of its base is $22\ m$. Find its total surface area.
Given: A cylinder, whose height is $3\ m$, is open from top. The circumference of its base is $22\ m$.
To do: To find the total surface area of the cylinder.
Solution:
As given
Let the radius of base be $r\ m$. Then,
Therefore, circumference of the cylinder base $=2\pi r=22$
$\Rightarrow 2\times\frac{22}{7}\times r=22$
$\Rightarrow r=\frac{7}{2}$
$h=3\ m$ [given]
Total Surface Area $=2 \pi rh+\pi r^2$
$=2\times\frac{22}{7}\times\frac{7}{2}\times3+\frac{2}{7}\times\frac{7}{2}\times\frac{7}{2}$
$=66+38.5$
$=104.5\ m^2$
Thus, the total surface area is $104.5\ m^2$.
Updated on: 10-Oct-2022
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