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A cone and a hemisphere have equal bases and equal volumes. Find the ratio in their heights.
Given:
A cone and a hemisphere have equal bases and equal volumes.
To do:
We have to find the ratio in their heights.
Solution:
Let $r$ be the radius of the cone and the hemisphere and $h$ be the height of the cone.
This implies,
Volume of the cone $=\frac{1}{3} \pi r^{2} h$
Volume of the hemisphere $=\frac{2}{3} \pi r^{3}$
Their volumes are equal.
Therefore,
$\frac{1}{3} \pi r^{2} h=\frac{2}{3} \pi r^{3}$
$\frac{1}{3} h=\frac{2}{3} r$
$\frac{h}{r}=\frac{2}{3} \times \frac{3}{1}$
$\frac{h}{r}=\frac{2}{1}$
The ratio in their heights is $2:1$.
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