A concave mirror produces magnification of +4. The object is placed:(a) at the focus (b) between focus and centre of curvature(c) between focus and pole (d) beyond the centre of curvature
(c) between focus and pole
Explanation
Given:
Magnification, $m$ =$+$4
Here, magnification is with the positive sign $(+)$, which implies that the image is virtual and erect.
$\because m>1\Rightarrow $ the size of the image is greater than that of the object.
In the case of the concave mirror, both of the above-mentioned conditions are only possible when the object is placed between its focus $(F)$ and pole $(P)$ in front of the mirror.
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