A car start from rest and acquire a velocity of 54 km/h in 2 sec. Find distance travelled by car assume motion of car is uniform?

Here, the initial velocity $u=0$

Final velocity $v=54\ km/h=54\times\frac{5}{18}\ m/s=15\ m/s$

Time $t=2\ sec.$

Therefore, acceleration $a=\frac{v-u}{t}$

$=\frac{15-0}{2}$

$=7.5\ m/s^2$

On using the equation of motion, $s=ut+\frac{1}{2}at^2$

Or $s=0+\frac{1}{2}\times7.5\times2^2$

Or $s=15\ m$

Therefore, the distance traveled by car is $15\ m$.

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Updated on: 10-Oct-2022

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