A car acquires a velocity of $72\ m/s$ in 10 seconds starting from rest. Find the distance travelled in this time.

Here initial velocity $u=0$

Final velocity $v=72\ km/h$

Time $t=10\ sec.$

Let $a$ be the acceleration of the car.

On using the equation, $v=u+at$

$72=0+a\times 10$

Or $10a=72$

Or $a=\frac{72}{10}=7.2\ m/s^2$

Let $s$ be the distance travelled by the car.

On using the equation $s=ut+\frac{1}{2}at^2$

Or $s=0\times10+\frac{1}{2}\times 7.2\times 10$

Or $s=0+36$

Or $s=36\ m$

Therefore, distance travelled is $36\ m$.

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Updated on: 10-Oct-2022

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