A ball of mass $200\ g$ falls from a height of $5\ metres$. What is its kinetic energy when it just reaches the ground? $(g=9.8 m/s^2)$.

Here given, mass of the ball $m=200\ kg=0.2\ kg$

Height $h=5\ m$

Gravitational acceleration $g=9.8\ m/s^2$

Therefore, the potential energy of the ball $P=mgh$

$=0.2\times9.8\times5$

$=9.8\ Joule$

When the boll reaches the ground, its total energy gets converted 

into kinetic energy.

Therefore, the kinetic energy of the ball is $9.8\ m/s^2$.

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Updated on: 10-Oct-2022

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