A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is neither white nor black.

Given:

A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag.

To do:

We have to find the probability that the ball drawn is neither white nor black.

Solution:

Number of black balls $=4$

Number of red balls $=8$

Number of white balls $=6$

Total number of balls $=4+8+6=18$

This implies,

The total number of possible outcomes $n=18$.

Here, neither white nor black implies red balls.

Total number of favourable outcomes(drawing a red ball) $=8$.

We know that,

Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$

Therefore,

Probability that the ball drawn is neither white nor black $=\frac{8}{18}$

$=\frac{4}{9}$

The probability that the ball drawn is neither white nor black is $\frac{4}{9}$.         

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Updated on: 10-Oct-2022

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