# A bag contains 7 white and 12 red balls. One ball is drawn at random from the bag. Find the probability of getting (a) a red ball (b) a white ball.

**Given :**

The total number of white balls in the bag $= 7$

The total number of Red balls in the bag $= 12$

**To find:**

We have to find the probability of getting (a) a red ball (b) a white ball.

**Solution :**

The total number of balls in the bag $= 7+12 = 19$

Therefore,

(a) The probability of drawing a red ball $= \frac{Number\ of\ red\ balls}{Total\ number\ of\ balls} = \frac{12}{19}$.

(b) The probability of drawing a white ball$ = \frac{Number\ of\ white\ balls}{Total\ number\ of\ balls} = \frac{7}{19}$.

**Therefore, the probability of getting a red ball is $\frac{12}{19}$ and a white ball is $\frac{7}{19}$.**

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