A bag contains 6 red, 8 black and 4 white balls. A ball is drawn at random. What is the probability that ball drawn is not black?

Given:

A bag contains 6 red, 8 black and 4 white balls. A ball is drawn at random.  

To do:

We have to find the probability that the ball drawn is not black.

Solution:

Number of red balls $=6$

Number of black balls $=8$

Number of white balls $=4$

Total number of balls $=6+8+4=18$

This implies,

The total number of possible outcomes $n=18$.

Here, not a black ball implies that the ball drawn is red or white.

Total number of favourable outcomes(drawing a red or white ball) $=6+4=10$.

We know that,

Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$

Therefore,

Probability that the ball drawn is not black $=\frac{10}{18}$

$=\frac{5}{9}$

The probability that the ball drawn is not black is $\frac{5}{9}$.  

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Updated on: 10-Oct-2022

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