$A (4, 2), B (6, 5)$ and $C (1, 4)$ are the vertices of $\triangle ABC$.The median from A meets BC in D. Find the coordinates of the point D.

Given:

$A (4, 2), B (6, 5)$ and $C (1, 4)$ are the vertices of $\triangle ABC$.

The median from A meets BC in D.

To do:

We have to find the coordinates of point D.

Solution:

$D$ is the mid-point of BC.

This implies,

Using mid-point formula, we get,

Coordinates of $D=(\frac{6+1}{2}, \frac{5+4}{2})$

$=(\frac{7}{2},\frac{9}{2})$ 

The coordinates of the point $D$ are $(\frac{7}{2},\frac{9}{2})$ .

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Updated on: 10-Oct-2022

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