$a^2+b^2=25$ and $ab=12$., then $a+b=?$.
Given: $a^2+b^2=25$ and $ab=12$.
To do: To find $a+b$.
Solution:
As given: $a^2+b^2=25$ and $ab=12$
$( a+b)^2=a^2+b^2+2ab$
$\Rightarrow ( a+b)^2=25+2( 12)$
$\Rightarrow ( a+b)^2=25+24$
$\Rightarrow ( a+b)^2=49$
$\Rightarrow ( a+b)=\pm\sqrt{49}$
$\Rightarrow ( a+b)=\pm7$
Thuus, $a+b=\pm7$.
Related Articles
- If $ab=5$ and $a^{2}+b^{2}= 25$, then what is $(a+b)^{2}=?$.
- If $ab=100$ and $a+b=25$, find the value of $a^2+b^2$.
- If $a + b = 10$ and $ab = 16$, find the value of $a^2 – ab + b^2$ and $a^2 + ab + b^2$.
- If $a=2$ and $b=-2$ find the value of $(i)$. $a^2+b^2$$(ii)$. $a^2+ab+b^2$$(iii)$. $a^{2}-b^2$
- If $a+b = 6$ and $ab = 8$, find $a^2+b^2$.
- If $a+b = 5$ and $ab =2$, find the value of $a^2+b^2$.
- Factorize the expression $49(a-b)^2-25(a+b)^2$.
- Factorize:\( 6 a b-b^{2}+12 a c-2 b c \)
- If a = 5 and b = $-$2 then the find the value of:(a $-$ b)2 $-$ (a $+$ b)2
- Solve by any method except cross multiplication$a(x+y)+b(x-y)=a^2-ab+b^2$ and $a(x+y)-b(x-y)=a^2+ab+b^2$
- Factorize:$a^2 + b^2 + 2(ab + bc + ca)$
- If \( x=\frac{\sqrt{a^{2}+b^{2}}+\sqrt{a^{2}-b^{2}}}{\sqrt{a^{2}+b^{2}}-\sqrt{a^{2}-b^{2}}} \), then prove that \( b^{2} x^{2}-2 a^{2} x+b^{2}=0 \).
- If a = 2 and b = 3 , find the value of1. $a + b$. $a^{2} + ab$ 3. $ab - a^{2}$4. $2a - 3b$5. $5a^{2} - 2ab$
- Identify the like termsa) \( -a b^{2},-4 b a^{2}, 8 a^{2}, 2 a b^{2}, 7 b,-11 a^{2},-200 a,-11 a b, 30 a^{2} \)\( \mathrm{b},-6 \mathrm{a}^{2}, \mathrm{b}, 2 \mathrm{ab}, 3 \mathrm{a} \)
- Factorise:$ab(x^2+y^2)-xy(a^2+b^2)$
Kickstart Your Career
Get certified by completing the course
Get Started