$500J$ of work is done to carry $x$ coulomb of charge between two points in $1$ second, having a potential difference of $100V$. Find the value of $x$.
Given:
Potential difference, $V$ = $100\ V$
Work done, $W$ = $500\ J$
To find: Amount of charge, $x$.
Solution:
We know that,
$W=V\times {Q}$
where, W = work done, and Q = Charge
Substituting the given value, we get-
$500=100\times {x}$ [x is the amount of charge flowing between two points at potential difference V = 100]
$x=\frac {500}{100}$
$x=5C$
Hence, 5 coulombs of charge are flowing between two points in 1 second having a potential difference of 100 V.
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