3 mL of ethanol is taken in a test tube and warmed gently in a water bath. A 5% solution of alkaline potassium permanganate is added first drop by drop to this solution, then in excess.(I) How is 5% solution of KMn04 prepared?(ii) State the role of alkaline potassium permanganate in this reaction. What happens on adding it in excess?(iii) Write chemical equation of this reaction.
(i) 5% solution of KMn04 is prepared by dissolving 5 grams of KMnO4 in 100 ml of water.
(ii) Alkaline potassium permanganate is adding oxygen to alcohol and converts it to acid. Hence, it acts as an oxidizing agent. When is KMn04 is added, initially colour disappears because coloured permanganate ions of potassium permanganate are consumed to oxidize ethanol.
When an excess of KMn04 is added, colour does not change because there is no more alcohol left for the reaction.
(iii) The chemical equation of this reaction is given below:
$C_2H_5OH(Ethanol) \xrightarrow{alkaline\ KMnO_4 +\ Heat}CH_3COOH (acetic\ acid)$
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