# $\mathrm{ABC}$ and $\mathrm{DBC}$ are two isosceles triangles on the same base $BC$ (see Fig. 7.33). Show that $\angle \mathrm{ABD}=\angle \mathrm{ACD}$."

#### Complete Python Prime Pack

9 Courses     2 eBooks

#### Artificial Intelligence & Machine Learning Prime Pack

6 Courses     1 eBooks

#### Java Prime Pack

9 Courses     2 eBooks

Given:

$ABC$ and $DBC$ are two isosceles triangles on the same base $BC$.

To do:

We have to show that $\angle ABD=\angle ACD$.

Solution:

Let us consider $\triangle ABD$ and $\triangle ACD$

We know that,

Side-Side-Side congruence rule states that if three sides of one triangle are equal to three corresponding sides of another triangle, then the triangles are congruent.

Since, $AD$ is the common side of the two triangles we get,

$AD=DA$

Since $ABC$ and $DBC$ are two isosceles triangles we get,

$AB=AC$ and $BD=CD$

Therefore,

$\angle ABD \cong \angle ACD$

We also know

From corresponding parts of congruent triangles: If two triangles are congruent, all of their corresponding angles and sides must be equal.

Therefore,

$\angle ABD=\angle ACD$.

Updated on 10-Oct-2022 13:41:10