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# $ \mathrm{ABC} $ and $ \mathrm{ADC} $ are two right triangles with common hypotenuse $ \mathrm{AC} $. Prove that $ \angle \mathrm{CAD}=\angle \mathrm{CBD} $.

Given:

\( \mathrm{ABC} \) and \( \mathrm{ADC} \) are two right triangles with common hypotenuse \( \mathrm{AC} \).

To do:

We have to prove that \( \angle \mathrm{CAD}=\angle \mathrm{CBD} \).

Solution:

We know that,

Angles in the same segment are equal.

This implies,

$\angle CBD=\angle CAD$

Hence proved.

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