In the given figure, if $∆ABE \cong ∆ACD$, show that $∆ADE \sim ∆ABC$.
"

AcademicMathematicsNCERTClass 10

Given:

$∆ABE \cong ∆ACD$

To do:

We have to show that $∆ADE \sim ∆ABC$.

Solution:

$\Delta ABE \cong \triangle ACD$

$AB=AC$             (CPCT)

$AE=AD$             (CPCT)

Therefore,

$\frac{AB}{AC}=\frac{AD}{AE}=\frac{1}{1}$

$\angle DAE=\angle BAC$

Therefore, by SAS criterion,

$\Delta ADE \sim \Delta ABC$

Hence proved.

raja
Updated on 10-Oct-2022 13:21:05

Advertisements