In the following APs, find the missing terms in the boxes:
$5, \square, \square, 9\frac{1}{2}$

Given:

Given AP is $5, \square, \square, 9\frac{1}{2}$

To do:

We have to find the missing terms in the box.

Solution:

$a=5$

$a_4=9\frac{1}{2}$

We know that,

$a_{4}=a+(4-1) d$

$5+3 d=\frac{19}{2}$

$3d=\frac{19}{2}-5$

$3d=\frac{19-10}{2}$

$3d=\frac{9}{2}$

$d=\frac{9}{2(3)}$

$d=\frac{3}{2}$

This implies,

$a_{2}=a+(2-1) d$

$=a+d$

$=5+\frac{3}{2}$

$=\frac{13}{2}$

$a_{3}=a_{2}+d$

$=\frac{13}{2}+\frac{3}{2}$

$=\frac{16}{2}$

$=8$

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

29 Views

Kickstart Your Career

Get certified by completing the course

Get Started