In the following APs, find the missing terms in the boxes:$-4, \square, \square, \square, \square, 6$

Given:

Given AP is $-4, \square, \square, \square, \square, 6$

To do:

We have to find the missing terms in the box.

Solution:

 $a=-4, a_{6}=6$

We know that,

$a_{n}=a+(n-1) d$

$a_{2}=a+d$

$=-4+2$

$=-2 $

$a_{3}=a_{2}+d$

$=-2+2$

$=0$

$a_{4}=a_{3}+d$

$=0+2$

$=2$

$a_{5}=a_{4}+d$

$=2+2$

$=4$