In figure below, if $ \angle \mathrm{D}=\angle \mathrm{C} $, then is it true that $ \triangle \mathrm{ADE} \sim \triangle \mathrm{ACB} ? $ Why?
"
Given:
\( \angle \mathrm{D}=\angle \mathrm{C} \)
To do:
We have to find whether \( \triangle \mathrm{ADE} \sim \triangle \mathrm{ACB} \).
Solution:
In $\triangle ADE$ and $\triangle ACB$,
$\angle A = \angle A$ (Common)
$\angle D = \angle C$ (Given)
Therefore, by AA similarity,
$\triangle ADE \sim \triangle ACB$
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