In Fig. 6.33, PQ and RS are two mirrors placed parallel to each other. An incident ray $ \mathrm{AB} $ strikes the mirror $ P Q $ at $ B $, the reflected ray moves along the path $ \mathrm{BC} $ and strikes the mirror $ \mathrm{RS} $ at $ \mathrm{C} $ and again reflects back along $ C D $. Prove that $ \mathrm{AB}=\mathrm{CD} $.
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AcademicMathematicsNCERTClass 9


raja
Updated on 10-Oct-2022 13:40:36

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