In a class A of 25 students, 20 passed with $ 60 \% $ or more marks; in another class B of 30 students, 24 passed with $ 60 \% $ or more marks. In which class was a greater fraction of students getting with $ 60 \% $ or more marks?
Given:
In a class A of 25 students, 20 passed with \( 60 \% \) or more marks; in another class B of 30 students, 24 passed with \( 60 \% \) or more marks.
To do:
We have to find in which class was a greater fraction of students getting with \( 60 \% \) or more marks
Solution:
Total number of students in Class A $= 25$
Students passed with 60% or more marks in Class A $= 20$
This implies,
Fraction of students passed with 60% or more marks $= \frac{20}{25}$
$= \frac{4}{5}$
Total number of students in Class B $= 30$
Students passed with 60% or more marks in Class B $= 24$
This implies,
Fraction of students passed with 60% or more marks $= \frac{24}{30}$
$= \frac{4}{5}$
Therefore, an equal fraction of students passed with 60% or more marks in both the classes.
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