In a class A of 25 students, 20 passed with $ 60 \% $ or more marks; in another class B of 30 students, 24 passed with $ 60 \% $ or more marks. In which class was a greater fraction of students getting with $ 60 \% $ or more marks?

Given:

In a class A of 25 students, 20 passed with \( 60 \% \) or more marks; in another class B of 30 students, 24 passed with \( 60 \% \) or more marks.

To do:

We have to find in which class was a greater fraction of students getting with \( 60 \% \) or more marks

Solution:

Total number of students in Class A $= 25$

Students passed with 60% or more marks in Class A $= 20$

This implies,

Fraction of students passed with 60% or more marks $= \frac{20}{25}$

$= \frac{4}{5}$

Total number of students in Class B $= 30$

Students passed with 60% or more marks in Class B $= 24$

This implies,

Fraction of students passed with 60% or more marks $= \frac{24}{30}$

$= \frac{4}{5}$

Therefore, an equal fraction of students passed with 60% or more marks in both the classes.