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If the lines given by $ 3 x+2 k y=2 $ and $ 2 x+5 y+1=0 $ are parallel, then the value of $ k $ is
(A) $ \frac{-5}{4} $
(B) $ \frac{2}{5} $
(C) $ \frac{15}{4} $
,b>(D) $ \frac{3}{2} $
Given:
The lines given by \( 3 x+2 k y=2 \) and \( 2 x+5 y+1=0 \) are parallel.
To do:
We have to find the value of \( k \).
Solution:
We know that,
The condition for parallel lines is,
$\frac{a_1}{a_2}=\frac{b_1}{b_2}≠\frac{c_1}{c_2}$
\( 3 x+2 k y=2 \) and \( 2 x+5 y+1=0 \) are parallel.
Here,
$a_1=3, b_1=2k, c_1=-2$
$a_2=2, b_2=5, c_2=1$
Therefore,
$\frac{3}{2}=\frac{2k}{5}≠\frac{-2}{1}$
$\frac{3}{2}=\frac{2k}{5}$
$2(2k)=5(3)$
$4k=15$
$k=\frac{15}{4}$
The value of $k$ is $\frac{15}{4}$.
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