If $p=-2$, find the value of:
$(i)$. $4p+7$
$(ii)$. $-3p^2+4p+7$
$iii)$. $-2p^3-3p^2+4p+7$

AcademicMathematicsNCERTClass 7

Given: 

$(i)$. $4p+7$

$(ii)$. $-3p^2+4p+7$

$iii)$. $-2p^3-3p^2+4p+7$


To do: To find the value of if $p=-2$.


Solution: 

$(i)$. $4p+7$


Putting $p=-2$


$=4(-2)+7$


$=-8+7$


$=-1$


$(ii)$. $-3p^2+4p+7$


Putting $p=-2$


$=-3(-2)^2+4(-2)+7$


$=-3(4)-8+7$


$=-12-8+7$


$=-13$


$(iii)$. $-2p^3-3p^2+4p+7$


Putting $p=-2$


$=-2(-2)^3-3(-2)^2+4(-2)+7$


$=-2(-8)-3(4)-8+7$


$=16-12-8+7$


$=3$

raja
Updated on 10-Oct-2022 13:38:20

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