How to handle the StringIndexOutOfBoundsException (unchecked) in Java?

Java Object Oriented Programming Programming

The StringIndexOutOfBoundsException is one of the unchecked exceptions in Java. A string is kind of an ensemble of characters. String object has a range of [0, length of the string]. When someone tries to access the characters with limits exceeding the range of actual string value, this exception occurs.

Example1

Live Demo

public class StringDemo {
   public static void main(String[] args) {
      String str = "Welcome to Tutorials Point.";
      System.out.println("Length of the String is: " + str.length());
      System.out.println("Length of the substring is: " + str.substring(28));
   }
}

Output

Length of the String is: 27
Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: -1
       at java.lang.String.substring(String.java:1931)
       at StringDemo.main(StringDemo.java:6)

How to handle the StringIndexOutOfBoundsException

We can check the range of the string using String.length() method and proceed to access the characters of it accordingly.
We can use try and catch block around the code snippet that can possibly throw StringIndexOutOfBoundsException.

Example2

Live Demo

public class StringIndexOutOfBoundsExceptionTest {
   public static void main(String[] args) {
      String str = "Welcome to Tutorials Point.";
      try {
        // StringIndexOutOfBoundsException will be thrown because str only has a length of 27.
str.charAt(28);
         System.out.println("String Index is valid");
      } catch (StringIndexOutOfBoundsException e) {
         System.out.println("String Index is out of bounds");
      }
   }
}

Output

String Index is out of bounds

Raja

Published on 27-Jun-2019 10:39:32

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